-0.9x^2+17x+25=0

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Solution for -0.9x^2+17x+25=0 equation:



-0.9x^2+17x+25=0
a = -0.9; b = 17; c = +25;
Δ = b2-4ac
Δ = 172-4·(-0.9)·25
Δ = 379
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{379}}{2*-0.9}=\frac{-17-\sqrt{379}}{-1.8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{379}}{2*-0.9}=\frac{-17+\sqrt{379}}{-1.8} $

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